is 0.5 kg ball is thrown up with an initial speed 40 metre per second and reaches a maximum height of 8.0 metre how much energy is dissipated by a drrag acting on the ball during the ascent
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The work done during the ascent is 9.8 J
Explanation:
Correct statement:
A 0.5 kg ball is thrown up with an initial speed 14 m/s and reaches a maximum height of 8.0 m . How much energy is dissipated by air drag acting on the ball during the ascent?
Mass of ball "m" = 0.5 Kg
speed "u" = 14 m/s
Work done = Change in energy
W = ΔE
W = mgh - 1/2 mv^2
= 0.5 x 9.8 x 8 - 1/2 x 0.5 x (14)^2
= 39.2 - 49
= - 9.8 Joule
The work done during the ascent is 9.8 J
The negative sign shows that the displacement and work done(force) are opposite in direction.
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