Question

is 0.5 kg ball is thrown up with an initial speed 40 metre per second and reaches a maximum height of 8.0 metre how much energy is dissipated by a drrag acting on the ball during the ascent ​

Answer 1

The work done during the ascent is 9.8 J

Explanation:

Correct statement:

A 0.5 kg ball is thrown up with an initial speed 14 m/s and reaches a maximum height of 8.0 m . How much energy is dissipated by air drag acting on the ball during the ascent?

Mass of ball "m" = 0.5 Kg

speed "u" = 14 m/s

Work done =  Change in energy

W = ΔE

W = mgh - 1/2 mv^2

    =  0.5 x 9.8 x 8 - 1/2 x 0.5 x (14)^2

    = 39.2 - 49

   = - 9.8 Joule

The work done during the ascent is 9.8 J

The negative sign shows that the displacement and work done(force) are opposite in direction.

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