Question

Is 1 ^ 11 + 2 ^ 11 + 3 ^ 11 + 4 ^ 11 divisible by 5 explain.

Answer 1

Q. 1^11+ 2^11+ 3^11+ 4^11

=1+2048+177147+4194304

=4373500

and the divisibility rule of 5 said that the no. last digit should be 0 or 5..

so, 4373500 last digit is 0.

therefore, 1^11+ 2^11+ 3^11+ 4^11 is divisible by 5..

thanks for it....

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