Question

is 1/3 a zero of p(x)=2x^3+3x^2-6x+7 explain​

Answer 1

Answer:

To find the given number is zero of the polynomial or not just put the value in all places of x if answer comes 0 then yes otherwise no.

Explanation:

Let's solve it

p(x) = $2x^{3} + 3x^{2} - 6x + 7$

Put x = 1/3

Note: P(x) must come zero to prove that that 1/3 is one of the zeroes of the polynomial

p (x) = $2(\frac{1}{3} )^{3} + 3(\frac{1}{3} )^{2} - 6*\frac{1}{3} + 7\\2*\frac{1}{27} + 3*\frac{1}{9} - 2 + 7\\\frac{2}{27} + \frac{1}{3} + 5\\\\LCM of all the numbers$

$\frac{2+9+27}{27} \\\\\frac{38}{27}$

this is not equal to zero so it is not one of the zero

If the question has -1/3 then it might me the zero of polynomial

Answer 2

Answer:

Hello thrisha, good morning, have a nice day..

Explanation: