Is (1) log 2 rational or irrational? Justify your answer.
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Answered by
1
Answer: Log 2 is irrational.
Answered by
2
Answer: Log 2 is irrational
Step-by-step explanation:
Short proof of “log 2 is irrational” :-
Assume that log 2 is rational, that is, log 2 = p / q .......... (i.)
where p, q are integers.
Since log 1 = 0 and log 10 = 1, 0 < log 2 < 1 and therefore p < q.
From (i.), 2 = 10 to the power p / q
= 2 to the power q = ( 2 * 5 ) to the power p.
= 2 to the power q - p = 5 to the power p , where q – p is an integer greater than 0.
Now, it can be seen that the L.H.S. is even and the R.H.S. is odd.
Hence, there is contradiction and log 2 is irrational.
Hope it helps :)
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