Question

Is 10 ×[(6+(- 2)]= 10X6+10x(-2)?

Answer 1

10× ( 6 -2) = 60 - 20x
10 ×4 = 60 -20x
40 = 60- 20x
40 -60 = 20x
-20 = -20 ×
-20/-20 =x

x=1

The value of x is 1
I hope it helps you

Answer 2

Concept Introduction:

The BODMAS rule is arranged according to the letters in the acronym BODMAS, which stand for brackets, order of powers or roots, division, and multiplication. A stands for addition and S for subtraction. According to the BODMAS rule, multi-operator mathematical equations must be resolved in the BODMAS order from left to right.

Given: $10 *[(6+(- 2)]= 10*6+10*(-2)$.

To Find:

We have to find the value of, LHS=RHS.

Solution:

According to the problem,

LHS, $10 *[(6+(- 2)]=10*(6-2)=10*4=40$

RHS, $10*6+10*(-2)=60-20=40$

∴ LHS=RHS.

Final Answer:

The value of LHS is equal to RHS. Therefore $10 *[(6+(- 2)]= 10*6+10*(-2)$.

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