Question

is 100 a term of the sequence 25, 28, 31

Answer 1

Step-by-step explanation:

$the \: given \: term \: ap \: is \: 25.28.31 \\ \\ its \: first \: term \: = 25 \\ and \: comman \: difference \: (28 - 25 ) = 3 \\ \\ (1)100 \: term \: of \: an \: ap \: \\ \\ t0100 = a + (n - 1)d \\ \\ 25 + (100 - 1)3 \\ \\ 25 + (297) \\ \\ t100 = 322$

hope it's helpful for uh ◉‿◉

Answer 2

Answer:

100 is the 26th term of the sequence given above with common difference 3 and first term 25.

HOPE THIS HELPS!