Question

is 101 a term of arithmetic sequence 13,24..

Answer 1

HOLA

===================

Given AP is 13 , 24

A = 13

D = 11

Tn = A + (N - 1) D

T 101 = 13 + ( 101n - 1) 11

T 101 = 13 + (1111n - 11)

T 101 = 13 + ( 1100)

T 101 = 1113

So the 101 term of the AP is 1113

================================


HOPE U UNDERSTAND ❤❤❤