is 101 a term of the AS having a=3, d=7
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Answered by
0
Answer:
Yes
3+7=10
10+7=17
17+7=24
24+7=31
31+7=38
38+7=45
45+7=52
52+7=59
59+7=66
66+7=73
73+7=80
80+7=87
87+7=94
94+7=101
=>so,101 is the term of the AS having a=3,d=7
Answered by
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in an AP a=3 , d=7
to find 101 is term of AP an=101
.
101 = 3 + (n-1) 7
101-3 = (n-1) 7
98 = 7n -7
98+7 = 7n
105=7n
n=105/7
n=15
therefore,101 is the 15th term of AP
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