Math, asked by balari72, 3 months ago

is
102
3 21
To divide a line segment AB in the ratio 6:7, a ray AX is drawn first such that <BAX is an acute
angle and then points A1, A2, A3,
are located equal distances on the ray AX. At
which point, B is joined ?
다.​

Answers

Answered by mohammadjasimhusain
0

Answer:

According to the question, A line segment AB in the ratio 6:7 So, A:B = 6:7 Now, Draw a ray AX making an acute angle BAX Minimum number of points located at equal distances on the ray, AX = A+B = 6+7= 13 A1, A2, A3, ………. are located at equal distances on the ray AX. Point B is joined to the last point is A13.

Similar questions