Question

Is 1188 a perfect cube? If not, by which smallest natural number should
1188 be divided so that the quotient is a perfect cube?​

Answer 1

Answer:

i dont know plz mark me as brainliest

Answer 2

$\huge \fbox \pink{Question:}$

Is 1188 a perfect cube? If not, by which smallest natural number should it be divided so that the quotient is a perfect cube?

$\huge \fbox \green{Answer:}$

$\textbf{Prime Factorising 1188 }$

$\fbox{we Get}$

$⇒1188 = 2 \times 2 \times 3 \times 3 \times 3 \times 11$

$= {2}^{2} \times {3}^{3} \times 11$

• We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, number of 2's is 2, number of 3's is 3 and number of 11's is 1.

• So we need to divide 2² and 11 from the factorization to make 1188 a perfect cube.

Hence, the smallest number by which 1188 must be divided to obtain a perfect cube is

${2}^{2} \times 11 = 44$

$\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$