Question

is 12. Of three numbers whose average is 60, the first is 1/4th of the sum of the others. What is the first number: A) 30 B) 42 C) 36 D) 45​

Answer 1

Answer:

$\qquad\qquad\underline{\textsf{\textbf{ \color{magenta}{Solution\:completed} }}}$

Question :-

• Of three numbers whose average is 60, the first is 1/4th of the sum of the others. What is the first number:
• A) 30
• B) 42
• C) 36
• D) 45

Solution :-

Let the no be x , y , z

Given ,

Avg of three no = 60

➙ ( x+y+z )/3 = 60

Also , x = (y+z)/4

➙ 4x = y +z

Put these in 1st eqn

➙ x +4x = 60 × 3

➙ 5x = 180

➙ x = 36

Henceforth, the first number is 36.

Correct options is C) 36

Answer 2

Solution

Let the no be x, y, 3

Given

AVG of three no. =60

.(x+y+2)/3=60

also x=(y t 3) 4

.4x=y t z

Put this in 1st eqn

.x+4x=60x3

.5x=180

.x=36

henceforth the first number is 36

Correct options is c. 36