Question

Is 128 a term of the series is 6 11 16 ......

Answer 1

Answer:

No

Step-by-step explanation:

In the given AP, a = 6, d = 5

128 = a + (n-1)d = 6 + (n-1)5

128-6 = 122 = 5(n-1)

122/5 = n-1

n = 122/5 + 1 = (122 + 5)/5 = 127/5 = 25.4

n can't be in decimals as a fractional number of term won't have any real existence. Thus, 128 can't be a term of the given series