is 128 the term series of 6+11+16.....?
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Answer:
NO
Step-by-step explanation:
first you write the difference which is 5 then multiply it by term(t) then add 1
5t + 1
why do we and 1
well if you multiply 5 by 1 it gives you 5 but the first term is 6 so we add one
try it out for 2nd and 3rd term.
finally to prove 128 is not part look a this
5t + 1 = 128
5t + 1 - 1 = 128 - 1
5t = 127
5t/ 5 = 127/ 5
t = a whole number with decimal
and a term can't be a number with decimal
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