Is -150 a term of an A.P : 11, 8, 5, 2,...?
Please tell me the answer with the steps :)
Answers
Answered by
0
Answer:
NO IT IS NOT IT'S TERM
Step-by-step explanation:
a = 11
d = 8-11 = -3
an = -150
an = a+ ( n-1 )d
an = 11 + ( n-1 ) -3
-150 = 11 -3n +3
-150 = -3n + 14
-3n = -150-14
-3n = -164
n = 164/3 = 54.666
since n is not coming as a perfect number hence -150 is NOT a term of the given AP
thanks :)
Similar questions