Is -150 a term of the A.P. 17,12,7,12...?
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Answered by
0
an =a+(n-1)d
-150=17+(n-1)-5
-150=17-5n+5
-150=22-5n
-150-22=-5n
-172=-5n
n =-172/-5=172/5=34.2
it is not in AP...
Answered by
10
Error :- there should be 2 instead of 12 in 4th term!!
an = -150
→ a1 = 17
→ a2 = 12
→ a3 = 7 and so on .
let us find common difference
→ d = a2 - a1
→ d = 12-17
→d = -5
→ an = a + (n - 1)d
→ -150 = 17 + (n - 1)5
→ -150 = 17 + 5n - 5
→ -150 = 12 + 5n
→ 5n = -150 - 12
→ 5n = -162
→ n = -162/5
HENCE IT IS NOT THE TERM OF AP
incrediblekaur:
gr8
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