Question

is 150 a term of the AP 11,8,5,2.....?​

Answer 1

Answer:

-436

Step-by-step explanation:

a=11,d=-3

$t_{150} =a+149d\\ =11+149(-3)\\ =11-447\\ =-436$

Answer 2

Answer:

(1) First term of AP is a = 11

(2) difference between two close number means d is 8-11= 5-8=2-5=-3

(3) Formula for nth number in AP is given by Tn= a+(n-1)d

T150 =11+(150-1)×-3

= 11 -149×3

= 11-447

= -436

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