Is - 156 a term of Ap 17,14,11,8.....?
Answers
Answered by
4
The ap is- 17,14,11,8.....
1st term = 17
2nd term= 14
Common difference=14-17= -3
Let (-156) be the nth term
a+(n-1)d = -156
17+(n-1)(-3)= -156
n= 176/3= 58.66
Since n has to be a whole number so (-156) is not a term of this ap
1st term = 17
2nd term= 14
Common difference=14-17= -3
Let (-156) be the nth term
a+(n-1)d = -156
17+(n-1)(-3)= -156
n= 176/3= 58.66
Since n has to be a whole number so (-156) is not a term of this ap
Answered by
3
Hey
Here is your answer,
First term, a = 17
Common difference, d = 14-17
=-3
An=-156
An = a+(n-1)d
-156 = 17 +(n-1)(-3)
-156-17/-3=n-1
-173/-3=n-1
n=173/3+1
n=173+3/3
n=176/3
Since the number of term is in fraction , it is not a term in a.p⬅⬅.
Hope it helps you!
Here is your answer,
First term, a = 17
Common difference, d = 14-17
=-3
An=-156
An = a+(n-1)d
-156 = 17 +(n-1)(-3)
-156-17/-3=n-1
-173/-3=n-1
n=173/3+1
n=173+3/3
n=176/3
Since the number of term is in fraction , it is not a term in a.p⬅⬅.
Hope it helps you!
Similar questions