Question

is 16 more than 12th term of an ap find the common difference of AP

Answer 1

Hey ! It's easy see
According to question ,
a12 + 16 = a16....................1)
an = a1 + (n-1) d ( where n is position of term)
a12 = a1 + (12-1)d
a12 = a1 + 11d .................2)

Similarly,. a16 = a1 + (16-1)d
a16 = a1 + 15d.......................3)
Substitute 2) and 3) in 1)

a1 +11d + 16 = a1 + 15d

16 = a1 - a1 + 15d - 11d
16 = 15d - 11d
16 = 4d
16/4 = d
4 = d ........answer
I hope this helps!!!!
- penmighter