Question

Is 1728 a perfect cube?

Answer 1

Yes 1728 is a perfect cube.
It is cube of 12.
12*12*12=1728. 


Thank you!

Answer 2

Answer:

1728 is a perfect cube.

Step-by-step explanation:

Resolving 1728 into product of prime factors,we get

2| 1728

________

2| 864

________

2| 432

________

2| 216

________

2| 108

________

2| 54

________

3| 27

________

3| 9

________

*** 3

$1728 = (2\times 2 \times 2 )\times (2\times 2 \times 2 )\times(3\times 3 \times 3)$

$= ( 2\times 2 \times 3)^{3}\\=12^{3}\: (Perfect \: cube)$

Therefore,

1728 is a perfect cube.

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