Question

Is 1728 a perfect cube? If yes, find the number
whose cube is 1728.​

Answer 1

Answer:

Yes 1728 is a perfect cube. It is cube of 12.

Answer 2

Answer:

1728 is the cube of 12.

Step-by-step explanation:

Resolving 216 into prime factors, we get

1728=3×3×3×2×2×2×2×2×2

Grouping the factor in triples of equal factor, we gate

1728=(3×3×3)×(2×2×2)×(2×2×2)

we find that prime factor of 1728 can be grouped into triples of equal factor and no factor is left over.

therefore, 1728 is perfect cube.

Taking one factor from each triple, we obtain

3×2×2= 12

Hence,1728 is the cube of 12.

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