Question

Is √27÷√9 is rational number​

Answer 1

$\Huge{\bold{\mathrm{\underline{\red{ANSWER}}}}}$

$\dfrac{ \sqrt{27} }{ \sqrt{9} } = \dfrac{3 \sqrt{3} }{3}$

$\sqrt{3}$

This is irrational .

Answer 2

Hi there!

$\huge\sf\pink{\frac{ \sqrt{27} }{ \sqrt{9} }}$

$\bf\green{1.732} \:( approx.)$

Which is equal to √2 which is an Irrational number.

So, It is irrational.

$\huge\red{\ddot\smile}$