Question

is √2x^2+7x+5√2=0 a quadratic equation if yes then give reason


Pls solve and then give the answer​

Answer 1

Answer:

Yes

Step-by-step explanation:

Yes this is a quadratic equation because the highest power of any quadratic equation is always 2.

Answer 2

${ \sqrt{2}{x}^{2} } + 7x + 5 \sqrt{2} = 0 \\ x = \frac{ - b \sqrt[ + - ]{ {b}^{2} - 4ac } }{2a} \\ = \frac{ - 7 \sqrt[ + - ]{ {( - 7)}^{2} - 4 \times \sqrt{2} \times 5 \sqrt{2} } }{2 \times \sqrt{2} } \\ = \frac{ - 7 \sqrt[ + - ]{49 - 40} }{2 \sqrt{2} } \\ = \frac{ - 7 \sqrt[ + - ]{9} }{2 \sqrt{2} } \\ = \frac{ - 7( + -)3}{2 \sqrt{2} } \\ \\ so \: \: \: \: \: \: \alpha = \frac{ - 7 + 3}{2 \sqrt{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ - 4}{2 \sqrt{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ - 2 \sqrt{2} }{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - \sqrt{2} \\ \\ and \: \: \: \: \: \: \beta = \frac{ - 7 - 3}{2 \sqrt{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ - 10 \sqrt{2} }{2 \sqrt{2} \times \sqrt{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ - 5 \sqrt{2} }{2}$

that is your answer.