Question

Is 30 KG box has to move opening line of slope of 30° to the horizontal at a uniform lost your 5 m if the frictional force be told in the motion is 150 N the horizontal force required to move up is

Answer 1

Answer:

346N

Explanation:

The force required to body up an inclined plane is

F=

$mg \: sin \theta \: + frictional \: force$

We will get 300

Horizontal force is

$\frac{F}{cos \theta}$

$300 \times \: \frac{2}{ \sqrt{3} } = 346 N</p><p>$

Answer 2

Answer:

346N

Explanation: