Is 302 a term of series 3+8+13+......, ?
Answers
Answered by
1
given that
a=3
d=5
according the law=
=a+(n-1)d=
=3+(n-1)5=302
=(n-1)5=299
=(n-1)=299/5
=(n-1)=59.8
if (n-1) is a fraction numbers
a=3
d=5
according the law=
=a+(n-1)d=
=3+(n-1)5=302
=(n-1)5=299
=(n-1)=299/5
=(n-1)=59.8
if (n-1) is a fraction numbers
Answered by
0
an=a+(n-1)d
302=3+(n-1)5
302-3=(n-1)5
299/5=n-1
n=294/5
n=58.LMK
302 is not the term for this given series
302=3+(n-1)5
302-3=(n-1)5
299/5=n-1
n=294/5
n=58.LMK
302 is not the term for this given series
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