Question

is 36 m. Find the area of the parallelogram.
Length of the diagonals of a rhombus are 24 m. and 10 m. Find the
length of its sides.​

Answer 1

Answer:

Let ABCD be the rhombus where, AC=10cm and BD=24cm

Let AC and BD intersect each other at O.Now, diagonals of rhombus bisect each other at right angles.

Thus, we have

AO=

2

1

×AC=

2

1

×10=5cm and

BO=

2

1

×BD=

2

1

×24=12cm

In right angled △AOB,

⇒ (AB)

2

=(AO)

2

+(BO)

2

⇒ (AB)

2

=(5)

2

+(12)

2

⇒ (AB)

2

=25+144

⇒ (AB)

2

=169

∴ AB=13cm

∴ The length of each side of rhombus is 13cm.

Answer 2

Answer:

Let d1 , d2 are diagonals of the Rhombus

d1 = 24cm

d2 = 10 cm

area = ( d1 d2 ) / 2

A = ( 24 × 10 ) / 2

A = 120 square cm

Let side if the Rhombus = a cm

a² = ( d1/2 )² + ( d2/2 )²

= ( 24 / 2 )² + ( 10 /2 )²

= ( 12 )² + 5²

= 144 + 25

= 169

a = √169

a = 13 cm

perimeter of the Rhombus = 4a

P = 4 × 13

P = 52 cm

I hope this helps you.