Question

is
38
2,5 moles of A, 3.5 moles of B, 3 moles of Cand 2,5 moles of 'D' are taken initially in one liter
container. At equilibrium, if 3 moles of 'D' exist in the container then K, for 3A +
B2C+Dii
x 4 lit/mole,​

Answer 1

Explanation:

(g)+B(g)⇌C(g)

moles

att=011.52

ateqb

m

1+x1.5+x2−x

Q

C

=

(1.5)(1.7)

127

=1.33

Reaction will be backward as concentration of C is less at equilibrium than at initial.

K

eq

=

[A][B]

[C]

=

[1+1.5][1.5+1.5]

[0.5]

=

[2.5][3]

[0.5]

=0.0666[∵2−x=0.5⟹x=0.5]

As Q

C

>K

eq

thus reaction will go in the backward direction.