Question

is 3x^2+4x-10 factorisable

Answer 1

Answer:

yes it is factorisable but you wil get value in root by middle term splitting but if you are in class 10th then you would know a method

d= b^2 - 4ac

d= (4)^2 - 4(3)(-10)

d= 16 +120

d= 136

now x= -b+root d/2a     and   -b - root d/2a

x = -4 + root 136/ 6     and  -4 - root 136 / 6

we can write root 136 as 2 root 34

so taking 2 as common to get

x =  -2 + root 34 / 3   and -2 - root 34/ 3

Step-by-step explanation:

if you have any more queries you can ask me on  [email protected]

Answer 2

Answer:

Yes, the given equation is factorisable using quadratic formula.

Step-by-step explanation:

$3x^2 + 4x - 10$

Compairing with standard form of polynomial, $ax^2 + bx + c$

a = 3, b = 4 and c = -10

Now, quadratic formula,

$x= \cfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$= \cfrac{-4 \pm \sqrt{4^2 - 4(3)(-10)}}{2(3)}$

$=\cfrac{-4\pm\sqrt{16+120}}{6}$

$=\cfrac{-4\pm\sqrt{136}}{6}$

$=\cfrac{-4\pm\sqrt{4\times 34}}{6}$

$=\cfrac{-4\pm2\sqrt{34}}{6}$

$=\cfrac{2(-2\pm\sqrt{34})}{6}$

$=\cfrac{-2\pm\sqrt{34}}{3}$ Ans.