Is 402 a term of sequence in 8,13,18,23..........?
Answers
Answered by
36
8,13,18,23.........
a=8
d=13-8=5
an=402
an=a+(n-1)d
402=8+(n-1)5
402-8=(n-1)5
394/5=(n-1)
394/5+1=n
399/5=n
402 is not a term of the sequence.
a=8
d=13-8=5
an=402
an=a+(n-1)d
402=8+(n-1)5
402-8=(n-1)5
394/5=(n-1)
394/5+1=n
399/5=n
402 is not a term of the sequence.
Answered by
10
no..... subtract any the larger digit from any smaller digit uh will get 5 or multiple of 5...for eg. 13-8=5......so subtract any of the above no. from 402 uh won't get a no which is divisible by 5
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