Question

is 45 m. EXERCISE 9A 1. If 15 oranges cost 110, what do 39 oranges cost? 2. If 8 kg sugar costs 260, how much sugar can be bought 3. The cost of 37 m of silk is * 6290. What length of this sill 4. A worker is paid 1110 for 6 days. If his total wages du- many days did he work? 5. A car can cover a distance of 357 km on 42 litres of petre of petrol? 6. Travelling 900 km by rail costs 7 2520. What would when a person travels by the same class? 7. A train covers a distance of 51 km in 45 minutes. Ho 8. If 22.5 metres of a uniform iron rod weighs 85.5 kg, vIf 8 kg sugar costs * 260, how much sugar can be bought for 877.50?​

Answer 1

Answer:

1. The answer is 4290

Step-by-step explanation:

110x39

is 4290

Answer 2

Answer:

1. Cost of 15 orange =Rs.110

Cost of 1 orange =Rs.(110/15)

∴ Cost of 39 orange =Rs.(110/15)×39

=Rs.286

2. 27 kg of sugar can be bought for Rs.877.50.

Step-by-step explanation:

Given : If 8 kg sugar costs Rs.260.

To find : How much sugar can be bought for Rs.877.50 ?

Solution :

Applying unitary method,

In Rs.260 we can buy 8 kg of sugar.

In Rs.1 we can buy \frac{8}{260}

260

8

kg of sugar.

In Rs.877.50 we can buy \frac{8}{260}\times 877.50

260

8

×877.50 kg of sugar.

In Rs.877.50 we can buy 27 kg of sugar.

Therefore, 27 kg of sugar can be bought for Rs.877.50.