Question

Is (5,6, 1) a Pythagorean triplet​

Answer 1

☘️Given:-

• Triplet Ser = (5,6,1)

☘️To Find:-

• Prove it a Pythagorean Triplet or Not.

☘️Solution:-

$\boxed{\pink{\sf{a²+b² = c²}}}$

${5}^{2} + {6}^{2} = {1}^{2}$

$25 + 36 = 1$

$61 = 1$

But here 61 ≠ 1, And it didn't satisfy the Rule a²+b² = c².

• So, It is not a Pythagorean Triplet.

$\Large{✓}$

Hope It Helps You ✌️