Question

Is 5 sec theta = 13 show that = 2 sin theta - 3 cos theta / 4 sin theta -9 cos theta

Answer 1

Sec theta=13/5
Cos theta= 5/13
Sin theta= 12/13
Friend put value and find answer.

Answer 2

5secA=13
SecA=13/5
Since SecA= 1/cosA
1/cosA= H/B= 13/5
Now,
H^2= P^2+B^2
(13)^2=P^2+(5)^2
169-25= P^2
P= (144)^1/2
P= 12
Now,
SinA= 12/13
CosA= 5/13
Now,
(2*12/13)-(3*5/13)/(4*12/13)-(9*5/13)
24-15/13/48-45/13
11/13/3/13
11/3