Question

is 5x-7y=-2 and 10x-14y=0

Answer 1

Hii Mate here Your Answer,

The solution of linear equation in two variable can be easily found by elimination and substitution method .

5x-7y = -2 ............. eq.1

10x - 14y = 0 ............. eq.2

Now let us eliminate y by multiplying A constant in LHS and RHS.

Multiply 2 in eq.1 = 10x - 14y = -4
(-)
Multiply 1 in eq.2 = 10x - 14y = 0
- + -
= 0 - 0 = -4

Hence LHS is not equal to RHS . So this equation has no solution. (Proved)

It can also be proved by comparing the Constants ÷

a1/a2 is not equal to b1/b2 has a single solution.

a1/a2 = b1/b2 but not equal to c1/c2 has no solution. I.e. this above equation.

a1/a2 = b1/b2 = c1/c2 has infinite number of solutions.

In the given equation,

a1/a2 = 5/10 = 1/2
b1/b2 = 7/14 = 1/2
c1/c2 = 2/0 = Not define

So a1/a2 = b1/b2 but not equal to c1/c2 that means it has no solutions.

☆☆☆HOPE THIS HELPS YOU A LOT ☆☆☆

Answer 2

Answer :

The two lines are

5x - 7y = - 2 ...(i)

and

10x - 14y = 0

=> 5x - 7y = 0 ...(ii)

These two lines (i) and (ii) are parallel lines and thus they will never intersect each other. So, we will not be able to find any solution to the given equations.

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