Question

Is 6 sin squared theta - 11 sin theta + 4 = 0 then find sin theta

Answer 1

Answer:

The value of $sin\theta\:\:is\:\frac{1}{2}$

Step-by-step explanation:

The given equation is factorized by spilitting its middle term.

$6sin^2\theta-11sin\theta+4=0\\\\6sin^2\theta-8sin\theta-3sin\theta+4=0\\\\2sin\theta(3sin\theta-4)-1(3sin\theta-4)-=0\\\\(2sin\theta-1)(3sin\theta-4)=0\\\\sin\theta=\frac{1}{2},\:\frac{4}{3}$

$But,\: -1\leq\:sinx\:\leq\:1$

Therefore,

$sin\theta=\frac{1}{2}$

Answer 2

Answer:

Sinθ = 1/2

Step-by-step explanation:

6 sin squared theta - 11 sin theta + 4 = 0 then find sin theta

6Sin²θ - 11Sinθ + 4 = 0

=> 6Sin²θ - 3Sinθ - 8Sinθ + 4 = 0

=> 3Sinθ(2Sinθ - 1) -4(2Sinθ -1) = 0

=>(3Sinθ -4)(2Sinθ - 1) = 0

Sin θ = 4/3  > 1 so not possible

Sinθ = 1/2