.Is 6125 a perfect cube? If not, by which smallest natural number should 1188 be divided so that the quotient is a perfect cube?
Answers
Answered by
1
Answer:
The prime factors of 6125 = 5×5×5×7×7
.°. 6125 is not a perfect cube
The smallest natural number should divide to 1188 so that the quotient is a perfect cube is 7×7=49
Now, 49 should divide 6125 so that the quotient is a perfect cube.
that means 6125 /49 = 125 = 5^3
Similar questions