is 68 a term 0f ap7,10,13....?
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Answered by
2
hey
an = a + (n-1)d
68 = 7 + (n-1)3
68 - 7 = (n-1)3
61/3 = n-1
n = 61/3 + 1
n = 64/3
therefore 68 is not a term of AP
Answered by
0
here first term, a = 7
common difference, d = 10 - 7 = 3
let the nth term be 68
so 68 = 7 + (n-1)3
=> 61 = ( n - 1)3
=> n-1 = 61/3
=> n = 61/3 + 1 = 64/3
here n is not a natural number
so 68 is not a term of the ap
hope it helps mark as brainliest
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