Is 68 is term of A.P 7,10,13........
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a=7
d=10-7=3
taking Tn = 68
Tn = a + (n-1)d
68 = 7 + (n-1)3
68 = 7 + 3n - 3
68 = 4 + 3n
64 = 3n
n =64 ÷ 3
as 64 is not divisible by 3
68 is not a term of AP
d=10-7=3
taking Tn = 68
Tn = a + (n-1)d
68 = 7 + (n-1)3
68 = 7 + 3n - 3
68 = 4 + 3n
64 = 3n
n =64 ÷ 3
as 64 is not divisible by 3
68 is not a term of AP
namanarora2001:
this is not correct answer
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3 8 13 18
we need to find which term is 78
an=a+(n-1)d
hence
an=78
a=3
d=8-3=5
the 16 term of ap is 78
we need to find which term is 78
an=a+(n-1)d
hence
an=78
a=3
d=8-3=5
the 16 term of ap is 78
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