is (6q+1)(6q+2)(6q+3) divisible by 6?
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Answer:
(6q+1)(6q+2)(6q+3)
in all 6q is common
then 6q is out
=6q(1+2+3)
=6q(6)
=36q/6
=6q
Yes, this is divisible by 6.
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