Math, asked by DhavalSolanki, 1 year ago

Is 9720 a perfect cube ? If not, find the smallest number by which it should be divided to get a perfect cube.

Answers

Answered by shadowsabers03
218

Let's factorize 9720 by LCM.


5 | 9720

2 | 1944

2 | 972

2 | 486

3 | 243

3 | 81

3 | 27

3 | 9

3 | 3

| 1


9720 = 5 x 2^3 x 3^5


∴ 9720 is not a perfect cube.


5 x 2^3 x 3^5 = 9720 divided by 5 x 3^2 = 45 gives a perfect cube. (9720 ÷ 45 = 216 = 2^3 x 3^3 = 6^3)


∴ 45 is the smallest number by which 9720 should be divided to get a perfect cube.


If the question was meant to find the whole number by which it should be divided to get a perfect cube, the answer will be 45.


But if the question was meant to find the smallest 'fraction', then the answer will be 5/3.


9720 divided by 5/3 gives 18^3.


Hope this may be helpful.


Please mark my answer as the brainliest if this may be helpful.


Thank you. Have a nice day.

Answered by drfatimanoush
21

Answer:

factorize 9720 byLCM

5 | 9720

2 | 1944

2 | 972

2 | 486

3 | 243

3 | 81

3 | 27

3 | 9

3 | 3

| 1

9720 = 5 x 2^3 x 3^5

so 9720 is not a perfect cube.

now to check smallest no. to be divided to make a perfect cube.. 5 x 3^2 = 45 gives a perfect cube. (9720 ÷ 45 = 216 = 2^3 x 3^3 = 6^3)

so 45 is the smallest no. to be divided by 9720 to make a perfect cube

mark me brainliest thnk u

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