Question

Is a 0 a term of AP:31,28,25...?

Answer 1

31, 28, 25

d = 28 - 31 = -3

a(n) = 0

⇒ a + (n - 1) d = 0

⇒ 31 + (n - 1)(-3) = 0

⇒ 31 -3n -3 = 0

⇒ 28 -3n = 0

⇒ -3n = 28

⇒ n = $\frac{28}{3}$

∴ 0 is not a term of the AP 31, 28, 25...