Math, asked by Tomboyish44, 1 year ago

Is (a-b) (a+b) + (b-c)(b+c) + (c-a)(c+a) = 0 , Yes or no ( reason not needed )

Answers

Answered by Cathenna
1
Given =>

(a - b)(a + b) + (b - c)(b + c) + (c - a)(c + a) = 0

Solving LHS

=> (a - b)(a + b) + (b - c)(b + c) + (c - a)(c + a)
(using formula (a - b)(a + b) = a² - b²)

=> a² - b² + b² - c² + c² - a²

=> 0

=> RHS

Therefore,

LHS = RHS

Hence Proved (Yes).

Tomboyish44: Thank you !!!!
Cathenna: Welcome!
Answered by Anonymous
1
Yes....it is correct...


(a+b)(a-b) + (b+c)(b-c) + (c+a)(c-a)
= a²-b² + b²-c² + c²- a
= 0

Tomboyish44: Thank You !!!
Tomboyish44: Oh okay
Similar questions