is (a+b+c) factor of a^2+ b^2-c^2+2ab
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Answered by
1
Correct option is
A
(a−b+c)
Given equation is a
2
−2ab−c
2
+b
2
We can write the given equation as,
⇒ a
2
−2ab+b
2
−c
2
⇒ (a−b)
2
−c
2
....Since (a
2
−2ab+b
2
=(a−b)
2
)
Also we know,
m
2
−n
2
=(m+n)(m−n)
Here, m=(a−b) and n=c
Thus a
2
−2ab−c
2
+b
2
=(a−b+c)(a−b−c)
Factors are (a−b+c) and (a−b−c).
A
(a−b+c)
Given equation is a
2
−2ab−c
2
+b
2
We can write the given equation as,
⇒ a
2
−2ab+b
2
−c
2
⇒ (a−b)
2
−c
2
....Since (a
2
−2ab+b
2
=(a−b)
2
)
Also we know,
m
2
−n
2
=(m+n)(m−n)
Here, m=(a−b) and n=c
Thus a
2
−2ab−c
2
+b
2
=(a−b+c)(a−b−c)
Factors are (a−b+c) and (a−b−c).
Answered by
0
Break it down into parts :-
|⠀⠀⠀⠀⠀⠀⠀⠀⠀|
⠀⠀⠀⠀⠀a²+b²-2ab = (a-b) (a-b)
⠀⠀⠀⠀⠀a²+b²-c²-2ab = (a-b)² - c²
⠀⠀⠀⠀⠀(a-b)²-c²=((a-b)+c)((a-b)-c)
⎆(a-b+c)(a-b-c)..
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