is a charge of 5.8 into 10 ki power minus 18 coulomb possible
Answers
Answer:
its 5.6 - 10^-16
Explanation:
Answer:
Is a charge of 5.8×10 to the power -18 possible?
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The value 5.8 × 10⁻¹⁸ is simply a number, not an electric charge. No measurement units, no charge—automatic loss of half credit for a homework or test answer if you were student in a class of mine, even if everything else is correct about handling the problem. (Far too many students regard measurement units as a pain in various parts of the body that they do not wish to bother with and have no importance to them, but the numeric part alone is meaningless without the unit—it is half of the value expression, and losing half the points for its absence causes a very quick high regard for units by the students, and use of units becomes a good habit.) My best guess, but it is only a guess with no certainty whatsoever of correctness, is that coherent SI units are being used so coulombs (symbol C) is meant—note that the unit name is not capitalized but the unit symbol is.
Since the elementary charge e is the quantum of free electric charge according to the currently adopted models, a free electric charge must be an integer times e. (Quarks do not count, even though they involve 1/3 or 2/3 of e, with either sign, currently adopted models do not allow them to be free but only bound together in ways that total an integer multiple of e.)
I am going to jump the gun here a bit and use the value 1.602 176 634 × 10⁻¹⁹ C for the elementary charge that is expected to be approved in 2018–11 as part of the basis for the redefinition of SI. This value will be correct and exact by definition. It has an infinite number of significant digits because it is a definition; however, from what needs to be typed in to a calculator or computer for calculations, it involves 10 digits—compared to the 2 significant digits given for the value in the posted question that is huge, so you do not need to calculate with all those digits. Remember to accommodate the level of precision of the value in the posted question.
How many elementary charges does this correspond to?
5.8 × 10⁻¹⁸ C / (1.602 2 × 10⁻¹⁹ C/e) = 36.20e.
Now, remember, the original value is good to only 2 significant digits, so the 36.20 is expressing more information content than really exists. The closest integer is 36. Let’s check whether the posted value is consistent with 36e, to the level of significance given:
36 × 1.602 176 634 × 10⁻¹⁹ C = 5.767 835 882 4 × 10⁻¹⁸, which, when rounded to 2 significant digits yields 5.8 × 10⁻¹⁸ C, the value given in the posted question once corrected for the missing unit.
Therefore, yes, there could be such a charge, which corresponds to 36 protons. (Remember, electrons are negative, and the posted charge did not have a negative sign—think of the symbol e as standing for elementary charge, which is unsigned to indicate a magnitude, rather than electron charge, which is negative.) This could be a nucleus of a krypton (Kr) atom.
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