Question

is a factor of pex) is each of the following
1. p(x) = x2 + 5x - 6 q(x) = (x - 1)​

Answer 1

Put x - 1 = 0

x = 1,

${x}^{2} + 5x - 6 \\ {1}^{2} + 5 \times 1 - 6 \\ 1 + 5 - 6 \\ 6 - 6 = 0 \\ hence \: (x - 1) \: is \: a \: factor \: of \: {x}^{2} + 5x - 6$

Hope it Helps ✌️✌️✌️

Answer 2

Hi

$p(x) = {x}^{2} + 5x - 6 \\ x - 1 = 0 \\ x = 1 \\ p(1) = {1}^{2} + 5 \times 1 - 6 \\ 1 + 5 - 6 \\ = 0$

Therefore x=0

q(x) is the factor of p(x).

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