Question

is a solution of equation x +y - 12 = 0
(AD(10,2) (B) (10,-2) (C) (14,-2
(D) (-2,-10)
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Answer 1

Answer:

answer is D I am correct

Step-by-step explanation:

$( - 2. - 10)$

Answer 2

Given:

x +y - 12 = 0

To find:

The equation's solution

Solution:

The required values of the solution are (10,2) and (14, -2).

We will have to substitute the given values of (x, y) in the given equation to determine the solution.

So, the given equation is x +y - 12 = 0.

i. On putting (10,2),

10+2-12=0

12-12=0

ii. On putting (10, -2),

10+(-2)-12=0

-4≠0

iii. On putting (14, -2),

14+(-2)-12=0

14-14=0

iv. On putting (-2, -10),

-2+(-10)-12=0

-12-12=-24≠0

So, (10,2) and (14, -2) are the required solutions.

Therefore, the required values of the solution are (10,2) and (14, -2).