θ is an acute angle, solve the following equations for θ:
(sec θ – 2) (tan 3 θ – 1) = 0
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Answered by
1
Answer: If 3Θ is an acute angle, solve the following equation Θ:(cosec3Θ−2)(cot2Θ−1)=0.
Step-by-step explanation:We have,
(csc3θ−2)(cot2θ−1)=0
Either,
csc3θ−2=0 or cot2θ−1
csc3θ=2,cot2θ=1
csc3θ=csc
6
π
,cot2θ=cot
4
π
3θ=
6
π
,2θ=
4
π
θ=
18
π
,θ=
8
π
Answered by
1
Answer:
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