Question

______ is an angle which is 32 degree more than its complement angle ​

Answer 1

$\large \red{ \sf \: solution} \\ \\ \large \rm \: let \: \: the \: \: angle \: \: be \: = x$

$\large \tt \star \: \: complement \: \: angle = 90 \degree$

$\large \tt \implies \: x + 32 \degree = 90 \degree- x \\ \\ \large \tt \implies \: x + x = 90 \degree - 32 \degree\\ \\ \large \tt \implies \: 2x = 58 \degree \\ \\ \large \tt \implies \: x = \frac{58 \degree}{2} \\ \\ \\ \large \underline{ \boxed{ \sf \: \therefore \: \: x = 29 \degree}}$