Question

is an isosceles triangle ABC with AB = AC the bisector of <B and < C intersect each other at O. join A to O show that :
i) OB=OC (ii)AO bisects <A ​

Answer 1

Answer:

a is boss of alphabet OK

sorry

Answer 2

Step-by-step explanation:

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Solution:-

Given:-

AB = AC and

the bisectors of B and C intersect each other at O

(i) Since ABC is an isosceles with AB = AC,

B = C

½ B = ½ C

⇒ OBC = OCB (Angle bisectors)

∴ OB = OC (Side opposite to the equal angles are equal.)

(ii) In ΔAOB and ΔAOC,

AB = AC (Given in the question)

AO = AO (Common arm)

OB = OC (As Proved Already)

So, ΔAOB ΔAOC by SSS congruence condition.

BAO = CAO (by CPCT)

Thus, AO bisects A.

$\large\bf{\underline\green{❥thαnk \; чσu ♥♥}}$