∆ is an isosceles triangle in which AB = AC , AD⏊ . Prove that ∠B = ∠C
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Answer:
AB=AC
⇒∠B=∠C (angles opp to equal sides are equal)
OR
in ΔABD n ΔACD
AB=AC (GIVEN)
AD=AD (COMMON)
∠ADB=∠ACD (90°)
ΔABD≅ΔACD (SAS CRITERIA)
⇒ ∠B=∠C (CPCT)
Step-by-step explanation:
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