Question

Is Anyone Tell Me The Answer of Those Question​

Answer 1

Heya

from which city are u ?

I'm from Pakistan too

Given :-

\begin{gathered}\leadsto \sf\bold{\pink{(x + 2) (x + 3) + (x - 3) (x - 2) - 2x(x + 1) =\: 0}}\\\end{gathered}⇝(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

To Find :-

What is the value of x.

Solution :-

\begin{gathered}\implies \sf (x + 2) (x + 3) + (x - 3) (x - 2) - 2x(x + 1) =\: 0\\\end{gathered}⟹(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

\begin{gathered} \implies \sf x(x + 3) + 2(x + 3) + x(x - 2) - 3(x - 2) - 2x(x + 1) =\: 0\\\end{gathered}⟹x(x+3)+2(x+3)+x(x−2)−3(x−2)−2x(x+1)=0

\begin{gathered} \implies \sf {x}^{2} + 3x + 2x + 6 + {x}^{2} - 2x - 3x + 6 - 2{x}^{2} - 2x =\: 0\\\end{gathered}⟹x2+3x+2x+6+x2−2x−3x+6−2x2−2x=0

\begin{gathered} \implies \sf {x}^{2} + {x}^{2} - 2{x}^{2} {\cancel{+ 3x}} {\cancel{+ 2x}} {\cancel{- 2x}} {\cancel{- 3x}} - 2x + 6 + 6 =\: 0\\\end{gathered}⟹x2+x2−2x2+3x+2x−2x−3x−2x+6+6=0

\begin{gathered} \implies \sf {\cancel{2{x}^{2}}} {\cancel{- 2{x}^{2}}} - 2x + 12 =\: 0\\\end{gathered}⟹2x2−2x2−2x+12=0

\implies \sf {\cancel{-}} 2x =\: {\cancel{-}} 12⟹−2x=−12

\implies \sf 2x =\: 12⟹2x=12

\implies \sf x =\: \dfrac{\cancel{12}}{\cancel{2}}⟹x=212

\implies \sf\bold{\red{x =\: 6}}⟹x=6

\therefore∴ {\large{\bold{\purple{\underline{The\: value\: of\: x\: is\: 6.}}}}}Thevalueofxis6.

Answer 2

Answer:

hi good night

bye