Is bisector of angle A and Angle B of a quadrilateral ABCD intersect each other at P of Angle B and angle C at Q of angle C and angles d at our and of Angle B and Angle A and S then pqrs is a rectangle rhombus parallelogram quadrilateral whose opposite sides are supplementary
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Given:
In quadrilateral ABCD, AS, BQ, CQ and DS are
angle bisectors of angles A, B, C and D, respectively.
∠QPS=∠APB
(Vertically opposite angles)
...(1)
In ∆APB,
APB+∠PAB+∠ABP=180∘
(Angle sum property of triangle.)
⇒ angle APB+1/2∠A+1/2∠B=180∘
⇒ angle APB=180∘–1/2(∠A+∠B)
...(2)
From (1) and (2), we get
angle QPS=180∘–1/2(∠A+∠B)
Similarly,
angle QRS=180∘–1/2(∠C+∠D)
...(3)
...(4)
From (3) and (4), we get
angleQPS+∠QRS=360∘–1/2(∠A+∠B+∠C+∠D
=360∘–1/2(360∘
= 360∘–180∘
=180∘
So, PQRS is a quadrilateral whose opposite angles are supplementary.
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